Optimal. Leaf size=142 \[ -\frac {7 a}{16 c^3 \left (a^2 x^2+1\right )}-\frac {a}{16 c^3 \left (a^2 x^2+1\right )^2}-\frac {a \log \left (a^2 x^2+1\right )}{2 c^3}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (a^2 x^2+1\right )}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (a^2 x^2+1\right )^2}+\frac {a \log (x)}{c^3}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}-\frac {\tan ^{-1}(a x)}{c^3 x} \]
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Rubi [A] time = 0.26, antiderivative size = 142, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 11, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.550, Rules used = {4966, 4918, 4852, 266, 36, 29, 31, 4884, 4892, 261, 4896} \[ -\frac {7 a}{16 c^3 \left (a^2 x^2+1\right )}-\frac {a}{16 c^3 \left (a^2 x^2+1\right )^2}-\frac {a \log \left (a^2 x^2+1\right )}{2 c^3}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (a^2 x^2+1\right )}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (a^2 x^2+1\right )^2}+\frac {a \log (x)}{c^3}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}-\frac {\tan ^{-1}(a x)}{c^3 x} \]
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 261
Rule 266
Rule 4852
Rule 4884
Rule 4892
Rule 4896
Rule 4918
Rule 4966
Rubi steps
\begin {align*} \int \frac {\tan ^{-1}(a x)}{x^2 \left (c+a^2 c x^2\right )^3} \, dx &=-\left (a^2 \int \frac {\tan ^{-1}(a x)}{\left (c+a^2 c x^2\right )^3} \, dx\right )+\frac {\int \frac {\tan ^{-1}(a x)}{x^2 \left (c+a^2 c x^2\right )^2} \, dx}{c}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}+\frac {\int \frac {\tan ^{-1}(a x)}{x^2 \left (c+a^2 c x^2\right )} \, dx}{c^2}-\frac {\left (3 a^2\right ) \int \frac {\tan ^{-1}(a x)}{\left (c+a^2 c x^2\right )^2} \, dx}{4 c}-\frac {a^2 \int \frac {\tan ^{-1}(a x)}{\left (c+a^2 c x^2\right )^2} \, dx}{c}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (1+a^2 x^2\right )}-\frac {7 a \tan ^{-1}(a x)^2}{16 c^3}+\frac {\int \frac {\tan ^{-1}(a x)}{x^2} \, dx}{c^3}-\frac {a^2 \int \frac {\tan ^{-1}(a x)}{c+a^2 c x^2} \, dx}{c^2}+\frac {\left (3 a^3\right ) \int \frac {x}{\left (c+a^2 c x^2\right )^2} \, dx}{8 c}+\frac {a^3 \int \frac {x}{\left (c+a^2 c x^2\right )^2} \, dx}{2 c}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a}{16 c^3 \left (1+a^2 x^2\right )}-\frac {\tan ^{-1}(a x)}{c^3 x}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (1+a^2 x^2\right )}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}+\frac {a \int \frac {1}{x \left (1+a^2 x^2\right )} \, dx}{c^3}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a}{16 c^3 \left (1+a^2 x^2\right )}-\frac {\tan ^{-1}(a x)}{c^3 x}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (1+a^2 x^2\right )}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}+\frac {a \operatorname {Subst}\left (\int \frac {1}{x \left (1+a^2 x\right )} \, dx,x,x^2\right )}{2 c^3}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a}{16 c^3 \left (1+a^2 x^2\right )}-\frac {\tan ^{-1}(a x)}{c^3 x}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (1+a^2 x^2\right )}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}+\frac {a \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )}{2 c^3}-\frac {a^3 \operatorname {Subst}\left (\int \frac {1}{1+a^2 x} \, dx,x,x^2\right )}{2 c^3}\\ &=-\frac {a}{16 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a}{16 c^3 \left (1+a^2 x^2\right )}-\frac {\tan ^{-1}(a x)}{c^3 x}-\frac {a^2 x \tan ^{-1}(a x)}{4 c^3 \left (1+a^2 x^2\right )^2}-\frac {7 a^2 x \tan ^{-1}(a x)}{8 c^3 \left (1+a^2 x^2\right )}-\frac {15 a \tan ^{-1}(a x)^2}{16 c^3}+\frac {a \log (x)}{c^3}-\frac {a \log \left (1+a^2 x^2\right )}{2 c^3}\\ \end {align*}
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Mathematica [A] time = 0.10, size = 118, normalized size = 0.83 \[ \frac {a x \left (-7 a^2 x^2+16 \left (a^2 x^2+1\right )^2 \log (x)-8 \left (a^2 x^2+1\right )^2 \log \left (a^2 x^2+1\right )-8\right )-15 a x \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2-2 \left (15 a^4 x^4+25 a^2 x^2+8\right ) \tan ^{-1}(a x)}{16 c^3 x \left (a^2 x^2+1\right )^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.59, size = 149, normalized size = 1.05 \[ -\frac {7 \, a^{3} x^{3} + 15 \, {\left (a^{5} x^{5} + 2 \, a^{3} x^{3} + a x\right )} \arctan \left (a x\right )^{2} + 8 \, a x + 2 \, {\left (15 \, a^{4} x^{4} + 25 \, a^{2} x^{2} + 8\right )} \arctan \left (a x\right ) + 8 \, {\left (a^{5} x^{5} + 2 \, a^{3} x^{3} + a x\right )} \log \left (a^{2} x^{2} + 1\right ) - 16 \, {\left (a^{5} x^{5} + 2 \, a^{3} x^{3} + a x\right )} \log \relax (x)}{16 \, {\left (a^{4} c^{3} x^{5} + 2 \, a^{2} c^{3} x^{3} + c^{3} x\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 135, normalized size = 0.95 \[ -\frac {\arctan \left (a x \right )}{c^{3} x}-\frac {7 \arctan \left (a x \right ) a^{4} x^{3}}{8 c^{3} \left (a^{2} x^{2}+1\right )^{2}}-\frac {9 a^{2} x \arctan \left (a x \right )}{8 c^{3} \left (a^{2} x^{2}+1\right )^{2}}-\frac {15 a \arctan \left (a x \right )^{2}}{16 c^{3}}+\frac {a \ln \left (a x \right )}{c^{3}}-\frac {a \ln \left (a^{2} x^{2}+1\right )}{2 c^{3}}-\frac {a}{16 c^{3} \left (a^{2} x^{2}+1\right )^{2}}-\frac {7 a}{16 c^{3} \left (a^{2} x^{2}+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.44, size = 181, normalized size = 1.27 \[ -\frac {1}{8} \, {\left (\frac {15 \, a^{4} x^{4} + 25 \, a^{2} x^{2} + 8}{a^{4} c^{3} x^{5} + 2 \, a^{2} c^{3} x^{3} + c^{3} x} + \frac {15 \, a \arctan \left (a x\right )}{c^{3}}\right )} \arctan \left (a x\right ) - \frac {{\left (7 \, a^{2} x^{2} - 15 \, {\left (a^{4} x^{4} + 2 \, a^{2} x^{2} + 1\right )} \arctan \left (a x\right )^{2} + 8 \, {\left (a^{4} x^{4} + 2 \, a^{2} x^{2} + 1\right )} \log \left (a^{2} x^{2} + 1\right ) - 16 \, {\left (a^{4} x^{4} + 2 \, a^{2} x^{2} + 1\right )} \log \relax (x) + 8\right )} a}{16 \, {\left (a^{4} c^{3} x^{4} + 2 \, a^{2} c^{3} x^{2} + c^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.57, size = 133, normalized size = 0.94 \[ \frac {a\,\ln \relax (x)}{c^3}-\frac {a\,\ln \left (a^2\,x^2+1\right )}{2\,c^3}-\frac {\frac {7\,a^3\,x^2}{2}+4\,a}{8\,a^4\,c^3\,x^4+16\,a^2\,c^3\,x^2+8\,c^3}-\frac {\mathrm {atan}\left (a\,x\right )\,\left (\frac {1}{a^2\,c^3}+\frac {25\,x^2}{8\,c^3}+\frac {15\,a^2\,x^4}{8\,c^3}\right )}{\frac {x}{a^2}+2\,x^3+a^2\,x^5}-\frac {15\,a\,{\mathrm {atan}\left (a\,x\right )}^2}{16\,c^3} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 2.51, size = 602, normalized size = 4.24 \[ \frac {16 a^{5} x^{5} \log {\relax (x )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {8 a^{5} x^{5} \log {\left (x^{2} + \frac {1}{a^{2}} \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {15 a^{5} x^{5} \operatorname {atan}^{2}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {30 a^{4} x^{4} \operatorname {atan}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} + \frac {32 a^{3} x^{3} \log {\relax (x )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {16 a^{3} x^{3} \log {\left (x^{2} + \frac {1}{a^{2}} \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {30 a^{3} x^{3} \operatorname {atan}^{2}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {7 a^{3} x^{3}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {50 a^{2} x^{2} \operatorname {atan}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} + \frac {16 a x \log {\relax (x )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {8 a x \log {\left (x^{2} + \frac {1}{a^{2}} \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {15 a x \operatorname {atan}^{2}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {8 a x}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} - \frac {16 \operatorname {atan}{\left (a x \right )}}{16 a^{4} c^{3} x^{5} + 32 a^{2} c^{3} x^{3} + 16 c^{3} x} \]
Verification of antiderivative is not currently implemented for this CAS.
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